Jika himpunan semesta S = {1, 2, 3, 4, 5, 6, 7, 8, 9}, A = {1, 3, 5} dan B = {2, 4, 6, 8}, maka Bc – A = ⋯
(A) {∅}
(B) {9}
(C) {7, 9}
(D) {1, 3, 5, 7, 9}
(E) {2, 4, 6, 7, 8, 9}

Jawab: (C)

  • Dari soal diketahui:
    • S = {1, 2, 3, 4, 5, 6, 7, 8, 9}
    • A = {1, 3, 5}
    • B = {2, 4, 6, 8}

Bc = komplemen B = anggota himpunan semesta (S) yang bukan merupakan anggota B. Sehingga Bc = {1, 2, 3, 4, 5, 6, 7, 8, 9} = {1, 3, 5, 7, 9}.

Operasi himpunan untuk Bc − A sama dengan anggota Bc yang bukan merupakan anggota A. Sehingga Bc – A = {1, 3, 5, 7, 9} = {7, 9}. Jadi, untuk S = {1, 2, 3, 4, 5, 6, 7, 8, 9}, A = {1, 3, 5} dan B = {2, 4, 6, 8}, maka Bc – A = {7, 9}.

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