UTBK 2019/PK
Operasi ⊙ pada himpunan bilangan bulat didefinisikan dengan aturan a ⊙ b = (a + b)b + 2. Nilai –2 ⊙ ((–1) ⊙ 2) adalah ….

(A)  7

(B)  12

(C)  10

(D)  16

(E)  25

Jawab: (C)

Aturan operasi yang diberikan: a ⊙ b = (a + b)b + 2

Untuk a = –1 dan b = 2, maka:

(–1) ⊙ 2 = (–1 + 2)×2 + 2

(–1) ⊙ 2 =  1×2 + 2 = 2 + 2 = 4

Sehingga,

–2 ⊙ ((–1) ⊙ 2) = –2 ⊙ 4

= (–2 + 4)×4 + 2

= 2×4 + 2

= 8 + 2

= 10

Jadi, nilai –2 ⊙ ((–1) ⊙ 2) adalah 10.

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