UTBK 2019/PK
Operasi ⊙ pada himpunan bilangan bulat didefinisikan dengan aturan a ⊙ b = a(b – 1) – a. Nilai 3 ⊙ (2 ⊙ 4) adalah ….
(A)  –6
(B)  0  
(C)  5
(D)  6
(E)  11

Jawab: (D)

Aturan operasi: a ⊙ b = a(b – 1) – a

Untuk a = 2 dan b = 4, maka:

2 ⊙ 4 = 2(4 – 1) – 2

2 ⊙ 4 = 2(3) – 2

2 ⊙ 4 = 6 – 2 = 4

Sehingga,

3 ⊙ (2 ⊙ 4) = 3 ⊙ 4

= 3(4 – 1) – 3

= 3(3) – 3

= 9 – 3 = 6

Jadi, nilai 3 ⊙ (2 ⊙ 4) adalah 6.

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