Nilai dari
3log √6 3log218 – 3log22
= ….

A.
1 8

B.
1 2


C. 1

D. 2

E. 8

Jawab: A

Penyelesaian dari soal fungsi logaritma dapat diselesaikan menggunakan sifat-sifat logaritma seperti langkah-langkah perhitungan berikut.

3log √6 3log218 3log22

=
3log 6½ (3log 18 – 3log 2)(3log 18 + 3log 2)

=
1/2 × 3log 6 3log (18 : 2) × 3log (18×2)

=
1/2 × 3log 6 3log 9 × 3log 36

=
1/2 × 3log 6 3log 9 × 3log 62

=
1/2 × 3log 6 2 × 2 × 3log 6

=
1/2 4
=
1 8


Jadi, nilai dari fungsi logaritma pada soal adalah 1/8.

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